echo: always allow to pass -e option
This will allow to do not taint if not enabled Signed-off-by: Jean-Christophe PLAGNIOL-VILLARD <plagnioj@jcrosoft.com> Signed-off-by: Sascha Hauer <s.hauer@pengutronix.de>
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@ -33,10 +33,9 @@ static int do_echo(int argc, char *argv[])
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int fd = stdout, opt, newline = 1;
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char *file = NULL;
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int oflags = O_WRONLY | O_CREAT;
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#ifdef CONFIG_CMD_ECHO_E
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char str[CONFIG_CBSIZE];
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int process_escape = 0;
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#endif
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/* We can't use getopt() here because we want to
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* echo all things we don't understand.
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*/
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@ -66,11 +65,9 @@ static int do_echo(int argc, char *argv[])
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goto no_optarg_out;
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optind++;
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break;
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#ifdef CONFIG_CMD_ECHO_E
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case 'e':
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process_escape = 1;
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process_escape = IS_ENABLED(CONFIG_CMD_ECHO_E);
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break;
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#endif
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default:
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goto exit_parse;
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}
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@ -89,13 +86,12 @@ exit_parse:
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for (i = optind; i < argc; i++) {
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if (i > optind)
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fputc(fd, ' ');
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#ifdef CONFIG_CMD_ECHO_E
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if (process_escape) {
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process_escape_sequence(argv[i], str, CONFIG_CBSIZE);
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fputs(fd, str);
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} else
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#endif
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} else {
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fputs(fd, argv[i]);
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}
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}
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if (newline)
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