license.bbclass: do not process LICENSE_pn variables
The loop iterating over LICENSE_pn variables has never worked. In addition, the LICENSE variable is supposed to contain all licenses defined in LICENSE_pn variables. Thus, it is simpler just to use LICENSE as the data we get is essentially the same. [YOCTO #9499] (From OE-Core rev: d7229489c7dfd35164fd107d7944f3c273776118) Signed-off-by: Markus Lehtonen <markus.lehtonen@linux.intel.com> Signed-off-by: Ross Burton <ross.burton@intel.com> Signed-off-by: Richard Purdie <richard.purdie@linuxfoundation.org>
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@ -387,20 +387,6 @@ def find_license_files(d):
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import oe.license
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from collections import defaultdict, OrderedDict
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pn = d.getVar('PN', True)
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for package in d.getVar('PACKAGES', True):
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if d.getVar('LICENSE_' + package, True):
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license_types = license_types + ' & ' + \
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d.getVar('LICENSE_' + package, True)
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#If we get here with no license types, then that means we have a recipe
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#level license. If so, we grab only those.
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try:
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license_types
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except NameError:
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# All the license types at the recipe level
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license_types = d.getVar('LICENSE', True)
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# All the license files for the package
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lic_files = d.getVar('LIC_FILES_CHKSUM', True)
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pn = d.getVar('PN', True)
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@ -498,7 +484,7 @@ def find_license_files(d):
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v = FindVisitor()
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try:
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v.visit_string(license_types)
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v.visit_string(d.getVar('LICENSE', True))
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except oe.license.InvalidLicense as exc:
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bb.fatal('%s: %s' % (d.getVar('PF', True), exc))
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except SyntaxError:
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