bitbake: bitbake-diffsigs: drop naive logic for removing duplicate files

This logic doesn't work in practice, certainly not with current versions
where sigdata files are preserved in the stamps directory and therefore
there will often be multiple sigdata files - you can now easily get
files for the same signature from sstate and the stamps directory with the
result that bitbake-diffsigs reports nothing has changed. Instead, let's
change the find_siginfo function in OE-Core to simply not return
duplicates so we don't have to filter them out here.

(Bitbake rev: f0d7ab259d8ef95643e7229474b7850608aa4426)

Signed-off-by: Paul Eggleton <paul.eggleton@linux.intel.com>
Signed-off-by: Richard Purdie <richard.purdie@linuxfoundation.org>
This commit is contained in:
Paul Eggleton 2017-04-07 09:52:04 +12:00 committed by Richard Purdie
parent 8f6094135b
commit d88a4ade7e
1 changed files with 0 additions and 16 deletions

View File

@ -37,12 +37,6 @@ logger = bb.msg.logger_create('bitbake-diffsigs')
def find_compare_task(bbhandler, pn, taskname):
""" Find the most recent signature files for the specified PN/task and compare them """
def get_hashval(siginfo):
if siginfo.endswith('.siginfo'):
return siginfo.rpartition(':')[2].partition('_')[0]
else:
return siginfo.rpartition('.')[2]
if not hasattr(bb.siggen, 'find_siginfo'):
logger.error('Metadata does not support finding signature data files')
sys.exit(1)
@ -59,16 +53,6 @@ def find_compare_task(bbhandler, pn, taskname):
logger.error('Only one matching sigdata file found for the specified task (%s %s)' % (pn, taskname))
sys.exit(1)
else:
# It's possible that latestfiles contain 3 elements and the first two have the same hash value.
# In this case, we delete the second element.
# The above case is actually the most common one. Because we may have sigdata file and siginfo
# file having the same hash value. Comparing such two files makes no sense.
if len(latestfiles) == 3:
hash0 = get_hashval(latestfiles[0])
hash1 = get_hashval(latestfiles[1])
if hash0 == hash1:
latestfiles.pop(1)
# Define recursion callback
def recursecb(key, hash1, hash2):
hashes = [hash1, hash2]