odoo
/
odoo
2
0
Fork 0
Code Pull Requests Releases Activity

[IMP] usability of menus by displaying their full hierarchy 

this will avoid confusion while organizing menu items hierarchy

bzr revid: abo@openerp.com-20121029145946-6fz0rvi7ewzbtp43
This commit is contained in:
Antonin Bourguignon 2012-10-29 15:59:46 +01:00
parent d45e2db49b d3a09bfcfc
commit 46e94a312c
1 changed files with 18 additions and 9 deletions
Show Stats Download Patch File Download Diff File Expand all files Collapse all files

25
openerp/addons/base/ir/ir_ui_menu.py
View File

@ -132,20 +132,29 @@ class ir_ui_menu(osv.osv):
return len(result)
return result
def _get_full_name(self, cr, uid, ids, name, args, context):
res = {}
for m in self.browse(cr, uid, ids, context=context):
res[m.id] = self._get_one_full_name(m)
def name_get(self, cr, uid, ids, context=None):
res = []
for id in ids:
elmt = self.browse(cr, uid, id, context=context)
res.append((id, self._get_one_full_name(elmt)))
return res
def _get_one_full_name(self, menu, level=6):
def _get_full_name(self, cr, uid, ids, name=None, args=None, context=None):
if context == None:
context = {}
res = {}
for elmt in self.browse(cr, uid, ids, context=context):
res[elmt.id] = self._get_one_full_name(elmt)
return res
def _get_one_full_name(self, elmt, level=6):
if level<=0:
return '...'
if menu.parent_id:
parent_path = self._get_one_full_name(menu.parent_id, level-1) + "/"
if elmt.parent_id:
parent_path = self._get_one_full_name(elmt.parent_id, level-1) + "/"
else:
parent_path = ''
return parent_path + menu.name
return parent_path + elmt.name
def create(self, *args, **kwargs):
self.clear_cache()